jeudi 18 janvier 2018

Parameter passing from JavaScript to PHP

My Ajax code as below;

 $.ajax({
                    type: 'POST',
                    url: '/sepetim/ajax',
                    data: {
                        '_token': $('input[name="_token"]').val(),
                        'name': $('input[name=name]').val(),
                        'cart_id': $('input[name=cart_id]').val(),
                        'stock_id': id
                    },
                    success: function(data) {
                       // alert(data.stock_id);
                        $('#5').replaceWith("<span class='para fw6'> TL</span>");

                       // $('#u').replaceWith(" <p class='para toplamfiyat'>55,08 TL</p>");
                    },
                });
                $('#name').val('');

My conroller as below;

public function  addStock(Request $request) {
        $data = new ShoppingCartDetail();
        $data->cart_id = $request->input('cart_id');
        $data->stock_id = $request->input('stock_id');
        $data->price = 1;
        $data->save();
        $data->x = 4;
        $data->price = 1200;
        return response ()->json ( $data );
      //return response()->json(["data" => $data]);
    }

I can get the values $data->price and $data->x in data but ajax success in part I can not print in.

ajax success function as below;

success: function(data) {
                       // alert(data.stock_id);
                        $('#5').replaceWith("<span class='para fw6'> TL</span>");

                       // $('#u').replaceWith(" <p class='para toplamfiyat'>55,08 TL</p>");
                    },

how can I pass data to this function in number_format()?



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